Thursday, September 2, 2010

3.HOW  DO YOU PROVE THIS EQUIVALENCE:BOOLEAN ALGEBRA?

(ABC+D)(E+F)+(A'+B'+C')D'E'F'=(ABC+D+E'F')(A'+B'+C')(D'+E+F)

1 comment:

  1. let us assume A=0,B=1,C=0,D=1,E=1,F=1.substituting these in LHS ,we get LHS=1.when the same is substituted in RHS ,we get RHS=1.By assuming other possible values for A,B,C,D,E,F we get LHS=RHS.
    so using the truth table this can be proved.

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